(log1p [x])Returns ln(1+x). For small values of x, log1p(x) is more accurate than
log(1.0+x).
If x is ##NaN or < -1 => ##NaN
If x is ##Inf => ##Inf
If x is -1 => ##-Inf
If x is 0 => 0 with sign matching x
See: https://docs.oracle.com/javase/8/docs/api/java/lang/Math.html#log1p-double-
Examples
No examples yet. Be the first to add one!